Ex 14.1 Q10 - A piggy bank contains hundred 50p coins, fifty ₹1 coins, twenty ₹2 coins and ten ₹5 coins

Ex 14.1 Q10 - A piggy bank contains hundred 50p coins, fifty ₹1 coins, twenty ₹2 coins and ten ₹5 coins. If it is equally likely that one of the coins will fall out when the bank is turned upside down, what is the probability that the coin (i) will be a 50 p coin ? (ii) will not be a ₹5 coin?

Ex 14.1 Q10 - A piggy bank contains hundred 50p coins, fifty ₹1 coins, twenty ₹2 coins and ten ₹5 coins. If it is equally likely that one of the coins will fall out when the bank is turned upside down, what is the probability that the coin (i) will be a 50 p coin ? (ii) will not be a ₹5 coin?

Solution:-

Given,
       No. of 50p coins = 100
       No. of ₹1 coins = 50
       No. of ₹2 coins = 20
       No. of ₹5 coins = 10

   ∴ Total coins = 100 + 50 + 20 + 10
                            = 180

   ∴ No. of Total outcomes = 180

*Formula to be used:-

P(Event) =
No. of favourable outcomes / No. of total outcomes

(i) Will be a 50p coin:-

We have,

      No. of 50p coins = 100
(Favourable outcome)

      No. of total coins = 180
       (Total outcome)

   ∴ P(getting a 50p coin)
   =
No. of 50p coins / No. of total coins
   =
100 / 180
   =
10 / 18
   =
5 / 9

   ∴ P(getting a 50p coin) =
5 / 9

Therefore, the probability of getting a 50p coin is 5/9.

(ii) Will not be a ₹5 coin:-

We have,

      No. of ₹5 coins = 10
(Favourable outcome)

      No. of total coins = 180
       (Total outcome)

   ∴ P(getting a ₹5 coin)
   =
No. of ₹5 coins / No. of total coins
   =
10 / 180
   =
1 / 18

➙ We know that, event of getting a ₹5 coin and event of not getting a ₹5 coin are complimentary event,

   ∴ P(getting a ₹5 coin) + P(not getting a ₹5 coin) = 1

   ∴ P(not getting a ₹5 coin)
   = 1 - P(getting a ₹5 coin)
   = 1 -
1 / 18
   =
18 - 1 / 18
   =
17 / 18

   ∴ P(not getting a ₹5 coin) =
17 / 18

Alternatively,

➙ According to question, the coin dropped from the piggy bank should not be of ₹5,

Then, it will be the coin of either 50p, ₹1 or ₹2.

   ∴ No. of (50p + ₹1 + ₹2) coins
   = 100 + 50 + 20
   = 170

   ∴ Favourable outcome = 170

      No. of total coins = 180
       (Total outcome)

   ∴ P(not getting a ₹5 coin)
   =
No. of coins except ₹5 / No. of total coins
   =
170 / 180
   =
17 / 18

   ∴ P(not getting a ₹5 coin) =
17 / 18

Therefore, the probability of not getting a ₹5 coin is 17/18.

Hence,
         The probability of getting a 50p coin and not getting a ₹5 coin is 5/9 and 17/18 respectively.
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Try This..

✒ A bag contains 4 white, 3 black, and 5 red balls. What is the probability that the ball picked is not black?

✒A card is drawn from a deck of 52 cards. What is the probability that it is a king?

✒ A box contains 3 red balls, 5 green balls, and 2 blue balls. Find the probability of getting a green ball.

❌ Common Mistakes

Not calculating total outcomes correctly:
▸ Always add all types of coins/items to get the correct total.

Mixing up favourable outcomes:
▸ Be clear whether the question is asking “what is” or “what is not” (like in part ii).

Not reducing fractions:
▸ Always simplify the final probability fraction unless it’s already in lowest terms.

Confusing coin values with quantity:
▸ In probability, we only care about number of coins, not their rupee values!

Queries Solved:-

Class 10 Ex 14.1
Ex 14.1 Q10 Class 10
Class 10 Ex 14.1 Q10
Class 10 Chap 14 Ex 14.1 Q10
Class 10 Probability

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