Ex 4.2 Q3 - Find two numbers whose sum is 27 and product is 182.

Ex 4.2 Q3 - Find two numbers whose sum is 27 and product is 182.

Ex 4.2 Q3 - Find two numbers whose sum is 27 and product is 182.

Solution:-

Let,
      First number = x
      Second number = y

Case (i): Given that, the sum of both numbers is 27,

   ∴ x + y = 27
   ∴ x = 27 - y       ------- (i)   

Case (ii): Also, the product of both numbers is 182,

   ∴ xy = 182
   ∴ (27 - y)y = 182       { from (i) }
   ∴ 27y - y² = 182
   ∴ y² - 27y + 182 = 0
   ∴ y² - 13y - 14y + 182 = 0
   ∴ y(y - 13) - 14(y - 13) = 0
   ∴ (y - 13) (y - 14) = 0

Now,

      y - 13 = 0          OR          y - 14 = 0
   ∴ y = 13                            ∴ y = 14


*Putting y = 13 in Eqⁿ(i)

   ∴ x = 27 - 13
   ∴ x = 14

*Putting y = 14 in Eqⁿ(i)

   ∴ x = 27 - 14
   ∴ x = 13

Hence,
          The required two numbers are 13 and 14.
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Try This..

✒ Two numbers differ by 5 and their product is 104. Find the numbers.

✒The sum and product of two numbers are 16 and 55 respectively. Find the numbers.

✒ The sum of two numbers is 30 and their product is 221. Find the numbers.

✒ Find two numbers whose sum is 20 and product is 96.

❌ Common Mistakes

Forgetting the signs:
▸ Always check the signs while expanding and factoring quadratic expressions.

Incorrect factor pairs:
▸ Make sure the numbers you pick for factoring actually multiply and add up to the required values.

Skipping standard form:
▸ Always write the quadratic in the ax² + bx + c = 0 format before solving.

Not verifying:
▸ Once you get the values, always plug them back to verify both the sum and product.

📝 Related Questions:-


Queries Solved:-

Class 10 Ex 4.2
Ex 4.2 Q3 Class 10
Class 10 Ex 4.2 Q3
Class 10 Chap 4 Ex 4.2 Q3
Class 10 Quadratic Equations

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